3. 290 : word pattern

s = str.split(' ')

class Solution(object):
    def wordPattern(self, pattern, str):
        s = str.split(' ')
        
        if len(s) != len(pattern):
            return False
       
        for i in range(len(s)):
            for j in range(i + 1, len(s)):
                if pattern[i] == pattern[j]:
                    if s[i] != s[j]:
                        return False
                else:
                    if s[i] == s[j]:
                        return False
            
        return True
        """
        :type pattern: str
        :type str: str
        :rtype: bool
        """

 

Posted by 공놀이나하여보세
,